## using factor theorem find the value of ‘a’ for which the polynomial (x^4 – x^3 – 11x^2 – x + a) is divisble by (x+3)

Question

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## Answers ( )

By factor Theorem

x + 3 = 0

x = -3

________________

p(x) = x⁴-x³-11x²-x+a = 0

p(-3) = (-3)⁴ – (-3)³ -(-3) + a = 0

81 + 27 +3 + a = 0

111 + a = 0

a = -111

_________________

Hence, value of a will be -111 for which p(x) will be divisible by (x+3)

Answer:By factor Theorem

x + 3 = 0

x = -3

________________

p(x) = x⁴-x³-11x²-x+a = 0

p(-3) = (-3)⁴ – (-3)³ -(-3) + a = 0

81 + 27 +3 + a = 0

111 + a = 0

a = -111

_________________

Hence, value of a will be -111 for which p(x) will be divisible by (x+3)

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