using factor theorem find the value of ‘a’ for which the polynomial (x^4 – x^3 – 11x^2 – x + a) is divisble by (x+3)​

Question

using factor theorem find the value of ‘a’ for which the polynomial (x^4 – x^3 – 11x^2 – x + a) is divisble by (x+3)​

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Maya 4 months 2021-09-24T14:44:37+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-24T14:45:52+00:00

    By factor Theorem

    x + 3 = 0

    x = -3

    ________________

    p(x) = x⁴-x³-11x²-x+a = 0

    p(-3) = (-3)⁴ – (-3)³ -(-3) + a = 0

    81 + 27 +3 + a = 0

    111 + a = 0

    a = -111

    _________________

    Hence, value of a will be -111 for which p(x) will be divisible by (x+3)

    0
    2021-09-24T14:46:32+00:00

    Answer:

    By factor Theorem

    x + 3 = 0

    x = -3

    ________________

    p(x) = x⁴-x³-11x²-x+a = 0

    p(-3) = (-3)⁴ – (-3)³ -(-3) + a = 0

    81 + 27 +3 + a = 0

    111 + a = 0

    a = -111

    _________________

    Hence, value of a will be -111 for which p(x) will be divisible by (x+3)

    Step-by-step explanation:

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