Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Then the numbers are: (

Question

Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Then the numbers are:

(A) 40, 42                                           

(B) 42, 48

(C) 40, 48                                           

(D) 44, 50

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Serenity 5 days 2021-11-25T01:50:15+00:00 2 Answers 0 views 0

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    0
    2021-11-25T01:51:33+00:00

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    Answer: (C) 40,48

    Explanation:

    According to given information

    x/y=5/6

    => 6x-5y=0 ……..(I)

    x-8/y-8=4/5

    => 5x-40=4y-32

    => 5x-4y=8 ………..(II)

    from eq. (I)

    6x-5y=0

    => x=5y/6

    substituting in……(II)

    5x-4y=8

    =>5[5y/6]-4y=8

    =>y/6=8

    =>y=48

    THEREFORE

    x=5y/6

    =>x=5×48/6

    => x=40

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    0
    2021-11-25T01:51:40+00:00

    Answer:

    Two numbers are in the ratio 5 : 6

    Let 5x, 6x be the two numbers

    Then by the given condition

    ( 5x 8) : ( 6x 8) = 4 : 5

    ( 5x – 8) / ( 6x – 8) = 4 / 5

    25x 40 = 24x 32

    25x 24x = 40 32

    x = 8

    So the required numbers are (5×8) = 40 & (6×8) = 48

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