The sum of ages of the father and the son is 48 yeas. The quotient obtained by dividing the age of the son by the age of the fa

Question

The sum of ages of the father and the son is 48 yeas. The quotient

obtained by dividing the age of the son by the age of the father is 1

5

.

Find their ages.​

in progress 0
Clara 5 days 2021-11-24T20:30:35+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-24T20:31:44+00:00

    Answer:

    let father’s age be X

    SONS AGE BE Y

    X/Y=1/5

    BY CROSS MULTIPLICATION

    5X=Y

    SUM OF AGES =48

    X+Y =48

    PUT VALUE OF Y

    Step-by-step explanation:

    6X =48

    X =8

    Y =40

    HOPE IT HELPS PLEASE MARK AS BRAINLIEST

    I THINK YOUR QUESTION IS WRONG BECAUSE BECAUSE FATHER’S AGE IS LESS THAN THE SUN AGE PLEASE CHECK IF THE FRACTION IS 5 BY 1 AUR 1 BY 5

    0
    2021-11-24T20:32:00+00:00

    \Huge\fbox{\color{red}{Answer}}

    Correct Question:- The sum of the age of father and the son is 48 year . the quotient obtained by dividing the age of son by the age of father is 1/ 5 .find their ages.

    Solution:- Let the age of father = x years

    Age of son = (48-x) years

    According to Question,

     \frac{48-x}{x}= \frac{1}{5}

    5×(48-x) = x

    240-5x=x

    240=x+5x

    240=6x

    x=  \frac{240}{6}

     \therefore x=40

    Now,age of father = x = 40 years

    Age of son = (48-x) years

    = 48-40 years

    = 8 years

    <body bgcolor=yellow><marquee direction="up"><font color=purple>

     \mathbb{MARK \:  IT \: AS \: BRAINLIEST}

Leave an answer

Browse

14:4+1-6*5-7*14:3+5 = ? ( )