The polynomial p (x)= x⁴-2x³+3x²-ax+3a-7 when divided by (x+1) leaves the remiander 19. Find the value of A and also divide it by (x+2)

Question

The polynomial p (x)= x⁴-2x³+3x²-ax+3a-7 when divided by (x+1) leaves the remiander 19. Find the value of A and also divide it by (x+2)

in progress 0
Eva 5 days 2021-11-24T20:57:34+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-24T20:58:58+00:00

    \huge\boxed{ \mathbb\red{❥A} \green{n} \mathbb\blue{S} \purple{w} \mathbb \orange{E} \pink{r}} \:

    ▪️Given:

    ▪️Polynomial p(x)=x⁴-2x³+3x²-ax+3a-7 which gives remainder 19 when divided by x+1

    ▪️To Find:

    ▪️Value of ‘a’.

    ▪️Value of remainder when p(x) is divided by x+2

    ▪️Solution:

    ▪️Dividend= x⁴-2x³+3x²-ax+3a-7

    ▪️Divisor= x+1

    ▪️Remainder= 19

    ▪️On dividing x⁴-2x³+3x²-ax+3a-7 by x+1, we get

    ▪️(Calculation in First attachment)

    ▪️Remainder= 4a-1

    ▪️Also, it is given that

    ▪️Remainder=19

    ▪️⇒ 4a-1= 19

    ▪️⇒ 4a= 20

    ▪️⇒ a= 5

    ▪️Now, after putting value of a in dividend, we get

    ▪️Dividend= x⁴-2x³+3x²-(5)x+3(5)-7

    ▪️Dividend= x⁴-2x³+3x²-5x+15-7

    ▪️Dividend= x⁴-2x³+3x²-5x+8

    ▪️Now,

    ▪️Dividend= x⁴-2x³+3x²-5x+8

    ▪️Divisor= x+2

    ▪️After dividing x⁴-2x³+3x²-5x+8 by x+2, we get

    ▪️(Calculation in second attachment)

    ▪️Remainder= 62

    ▪️Hence, the value of a is 5 and required remainder is 62.

    Hopes it help you✌️✌️

    0
    2021-11-24T20:59:24+00:00

    hope it will help you kindly mark the answer as brainlist

Leave an answer

Browse

14:4+1-6*5-7*14:3+5 = ? ( )