The perimeter of triangular field is 270 metre and it’s sides are in the ratio 25 : 17 : 12. Find its area . ​

Question

The perimeter of triangular field is 270 metre
and it’s sides are in the ratio 25 : 17 : 12. Find its area .

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Elliana 2 months 2021-11-23T04:09:15+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-23T04:10:29+00:00

    Step-by-step explanation:

    perimeter is the sum of all sides

    let side will be X.( 25x) (17x) (12x)

    so, 25x+17x+12x = 270

    54x = 270

    X = 5

    the three side will be

    25x = 25*5 = 125

    17x = 17*5 = 85

    12x = 12*5 = 60…..

    HOPE THIS WILL HELP YOU ….

    AND PLEASE FOLLOW ME …..

    0
    2021-11-23T04:11:11+00:00

    Answer:

    perimeter of triangle = sum of sides

    so let sides be a= 25x , b= 17x c= 12x

    25x + 17x + 12x = 270

    54x = 270

    x= 5

    now the actual sides are , a= 25 x 5 = 125 m

    b= 17 x 5 = 85 m

    c= 12 x 5 = 60 m

    now we find semiperimeter ( S) i. e 270/2 = 135 m

    area of triangle ,by heron’s formula = ✓S( S-a) (S-b) (S-c)

    = ✓135( 135-125) (135-85) (135-60)

    = ✓135( 10 ) (50) (75)

    = √3x45x 5x2x5x5x2x5x5x3

    = √ 3x3x3x5x5x2x5x5x2x5x5x3

    = 5x5x5x3x3x2

    = 2250 sq.m

    here

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