## The middle digit pf a three digit number is 0 and the sum of the other two digit is 11 .if the number obtained by reversing the digit exceed

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## 308 is the original number.

Step-by-step explanation:Let the number at 100s place be x

Let the number at ones’ place be y

Given that,

x + 0 + y = 11

or

x = 11 – y …(i)

Given that,

If the original number on reversing gives a new number that exceeds the original no. by 495, the equation would be:

100x + a = 100x + y + 495

99y – 99x = 495

⇒ 11y – 11x = 55 …(ii)

By substituting the value of x from equation (i)

11y – 11(11-y) = 55

11y – 121 + 11y = 55

22y = 176

y = 176/22

y = 8

Therefore,

x = 11 – 8

x = 3.Hence,

the original number is308.

Verify;

803 – 308 = 495

3 + 0 + 8 = 11.

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