The first four terms of an A.P.having the first term -7 and common difference 3 are

Question

The first four terms of an A.P.having the first term -7 and common difference 3 are

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Arianna 2 weeks 2021-11-15T06:07:21+00:00 2 Answers 0 views 0

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    0
    2021-11-15T06:09:02+00:00

    Given , the first term= 7

    common difference =3

    first four terms would be a1=7

    second term a1+d=7+3=10

    third term would be a1+2d = 7+2(3) = 13

    fourth term would be a1+3d = 7+3(3) = 15

    so the first four terms would be 7, 10 ,13 ,15

    0
    2021-11-15T06:09:09+00:00

    GivEn:-

    • First term of AP (a) = -7
    • Common difference (d) = 3

    To find:-

    • First four terms of AP.

    SoluTion:-

    As we know that,

    • First term of AP (a) = -7
    • Second term \sf ( a_2 ) = a + d = -7 + 3 = -4
    • Third term \sf ( a_3 ) = a + 2d = -7 + 2 × 3 = -7 + 6 = -1
    • Fourth term \sf ( a_4 ) = a + 3d = -7 + 3 × 3 = -7 + 9 = 2

    We know that,

    \sf a, a_2 , a_3 , a_4 ,.....a_n

    Hence, Required AP is,

    ➟ -7, -4, -1, 2,…..\sf a_n

    ━━━━━━━━━━━━━━━

    Additional Information:-

    Formula related to AP –

    ★ To find \sf a_n term of AP,

    ⠀⠀⠀✩ \sf a_n = a + (n - 1)d

    ★ To find Sum of n terms \sf( S_n ) of AP,

    ⠀⠀⠀✩ \sf S_n = \dfrac{n}{2} \bigg( 2a + (n - 1)d \bigg)

    ━━━━━━━━━━━━━━━

    ⠀⠀⠀⠀⠀⠀⠀

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