The center of a circle is (a+2, a-1). find a if the circle passes through (2,-2) and (8-2)​

Question

The center of a circle is (a+2, a-1).
find a
if the circle passes through
(2,-2) and (8-2)​

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Brielle 4 days 2021-10-09T23:37:14+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-09T23:38:36+00:00

    Answer: I have tried to solve….

    May this will help you…

    If there is any confusion tell

    0
    2021-10-09T23:38:55+00:00

    Sol: Points on the circle are (2, -2) and (8, -2) Centre of the circle = (a+2, a-1) Distance between (a+2, a-1) and (2, -2) = Distance between (a+2, a-1) and (8, -2) √[(2-a-2)2 + (-2-a+1)2] = √[(8-a-2)2 + (-2-a+1)2] √[(-a)2 + (-1-a)2] = √[(6-a)2 + (-1-a)2] Squaring on both sides, a2 + 1 + a2 + 2a = 36 + a2 – 36a + 1 + a2 + 2a 2a + 1 = 37 – 34a 36a= 36 a = 1 Hence, the value of a is 1.

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