A natural number is divisible by 3 if and only if the sum of it’s digits is divisible by 3. Eg : 4) 3+7+4+6+1 = 21 ; which is divisible by 3

A natural number is divisible by 9 if and only if the sum of it’s digits is divisible by 9. Eg : 3) 1+4+3+0+1 = 9 which is divisible by 9

A natural number is divisible by 6 only if the number is divisible by 2 and 3 .

For a no. to be divisible by 2 it must be an even no. and for the divisibility property of 3 refer above . Eg : 3) which is even (divisible by 2) and also divisible by 3 ; so it is divisible by 6

## Answers ( )

Answer:1) not divisible by any of the numbers

2) divisible by 3 and 6 only

3) divisible by 3 and 9

4) divisible by 3 only

Step-by-step explanation:A natural number is divisible by 3 if and only if the sum of it’s digits is divisible by 3. Eg : 4) 3+7+4+6+1 = 21 ; which is divisible by 3

A natural number is divisible by 9 if and only if the sum of it’s digits is divisible by 9. Eg : 3) 1+4+3+0+1 = 9 which is divisible by 9

A natural number is divisible by 6 only if the number is divisible by 2 and 3 .

For a no. to be divisible by 2 it must be an even no. and for the divisibility property of 3 refer above . Eg : 3) which is even (divisible by 2) and also divisible by 3 ; so it is divisible by 6

Please mark my answer as the brainliest answer .

It took me a long time to type and explain .

Hope it helped you .