11 {x }^{2} + 26x + 21

Question

11 {x }^{2}  + 26x + 21

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Rylee 3 months 2021-11-06T14:43:23+00:00 1 Answer 0 views 0

Answers ( )

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    2021-11-06T14:44:25+00:00

    \bf\purple{\underline{\boxed{Question}}}

    \:

    \small\tt{11 {x }^{2} + 26x + 21}

    \:

    \bf\purple{\underline{\boxed{Solution}}}

    \:

    \tt{11x^{2}+26x+21}

    \:

    \small\tt{where\:\:,}

    \small\tt{a\:=\:11}

    \small\tt{b\:=\:26}

    \small\tt{c\:=\:21}

    \:

    \small\tt{using\: formula\:\:D\:=\:b^{2}-4ac}

    \:

    \small\tt{\:=\:26^{2}-4\times11\times21}

    \small\tt{\:=\:676\:-\:924}

    \small\tt{D\:=\: -248}

    \:

    \small\tt{using\: formula\:\:}

    \:

    \tt{x\:=\:\frac{-b±\sqrt{ \ b^{2}-4ac}}{2a}}

    \:

    \tt{x\:=\:\frac{-(26)±\sqrt{-248}}{2\times 11}}

    \tt{x\:=\:\frac{-26±\sqrt{ -248}}{22}}

    \:

    \small\tt{There\:are\:2\:possible\:values}

    \:

    \small\tt{1)\:\:Postive\:}

    \tt{x\:=\:\frac{-26+\sqrt{ -248}}{22}}

    \:

    \small\tt{2)\:\:Negetive\:}

    \tt{x\:=\:\frac{-26-\sqrt{ -248}}{22}}

    \:

    \bf\purple{\underline{\boxed{Thanks}}}

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