Susheela travelled (15m^2n+25mn^2+5mn) km in 5mn hours. Find the speed

Question

Susheela travelled (15m^2n+25mn^2+5mn) km in 5mn hours. Find the speed

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Mary 2 weeks 2021-11-15T08:08:50+00:00 1 Answer 0 views 0

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    2021-11-15T08:09:50+00:00

    Step-by-step explanation:

    Distance travelled by Susheela,(15m²n+25mn²+5mn)km

    Time taken= 5mn hours

    Therefore, (15m²n+25mn²+5mn) ÷ 5mn

    = 5mn×(3m+2n+1) ÷ 5mn [Taking common factor]

    = 3m+2n+1 [Satisfying 5mn by 5mn=1]

    Therefore, the Avg. speed is 3m+2n+1

    Hope it helps!

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