solve the quadratic equation -x^2+7x-10=0​

Question

solve the quadratic equation -x^2+7x-10=0​

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Mary 3 days 2021-10-11T04:52:36+00:00 2 Answers 0 views 0

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    0
    2021-10-11T04:53:43+00:00

    Answer:

    x^2+7x-10=0(by factorization method

    Step-by-step explanation:

    x^2-5x-2x-10=0

    x(x-5) 2(x-5)

    (x-5) (x+2)=0

    (x+2)=0  (x-5)=0

    x=-2   x=5

    0
    2021-10-11T04:54:26+00:00

    Answer:

    x=5, x=2

    Step-by-step explanation:

    Given Equation is-x^2+7x-10=0

    =>-x^2+7x-10=0

    =>-(x^2-7x+10)=0

    =>x^2-5x-2x+10=0         (Since by splitting’-7x’)

    =>x(x-5)-2(x-5)=0

    =>(x-5)(x-2)=0

    =>x-5=0 or x-2=0

    =>x=5    or    x=2

    therefore,

    the roots of the given quadratic equation are 5 and 2

    HOPE THIS WOULD BE HELPFUL FOR YOU

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