solve the quadratic equation x^2-3√5x+10=0 AND -x^2+7x-10=0​

Question

solve the quadratic equation x^2-3√5x+10=0 AND -x^2+7x-10=0​

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Josie 4 days 2021-10-11T07:40:56+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-11T07:42:27+00:00

    Step-by-step explanation:

    hope it helps you ……..

    0
    2021-10-11T07:42:39+00:00

    Answer:

    Solution:

    Given quadratic equation:

    x²-3√5x+10=0

    Splitting the middle term, we

    get

    => x²-2√5x-√5x+10=0

    => x²-2√5x-√5x+2×5=0

    => x²-2√5x+√5x +2×√5×√5=0

    => x(x-2√5)-√5(x-2√5)=0

    => (x-2√5)(x-√5)=0

    => x-2√5 =0 Or x-√5 = 0

    => x = 2√5 Or x = √5

    Therefore,

    Roots of given Quadratic equation are:

    2√5 Or √5

    •••••

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