Solve the following linear equation :- 4x – 3y = 8 and x – 2y = -3​

Question

Solve the following linear equation :- 4x – 3y = 8 and x – 2y = -3​

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Charlie 7 hours 2021-10-13T04:09:13+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-13T04:10:16+00:00

    Step-by-step explanation:

    4x – 3y = 8

    x – 2y = -3

    x = -3 + 2y

    x = 2y -3

    substituting x= 2y-3 in 4x – 3y = 8

    4(2y-3) – 3y = 8

    8y – 12 – 3y = 8

    5y -12 = 8

    5y = 8+12

    5y = 20

    y=20/5

    y=4

    x=2y – 3

    x= 2(4)-3

    x=8-3

    x=5

    0
    2021-10-13T04:10:52+00:00

    Answer:

    4x-3y=8

     x = \frac{8 + 3y}{4}

    put value of x in equation 2

    x-2y=-3

     \frac{8  + 3y}{4}  - 2y =  - 3

     \frac{8 + 3y - 8y}{4}  =  - 3

    8-5y=-12

    -5y=-20

    y=4

    put value of y in equation 1

    x =  \frac{8 + 3y}{4}  =  \frac{20}{4}  = 5

    hence,x=5 and y=4

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