## Solve 8x+5y=9 3x+2y=4 by elimination method

Question

Solve 8x+5y=9
3x+2y=4 by elimination method

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4 months 2021-09-24T18:15:09+00:00 2 Answers 0 views 0

2. Step-by-step explanation:

Hi friend,

Hi friend,By elimination method :

Hi friend,By elimination method :8x+5y = 9———(1) ×2

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 18

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 9

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 95y = 9+16

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 95y = 9+165y = 25

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 95y = 9+165y = 25y = 25/5

Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 95y = 9+165y = 25y = 25/5y = 5