Solve 8x+5y=9 3x+2y=4 by elimination method

Question

Solve 8x+5y=9
3x+2y=4 by elimination method

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Delilah 4 months 2021-09-24T18:15:09+00:00 2 Answers 0 views 0

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    0
    2021-09-24T18:16:37+00:00

    Answer:

    I hope this answer will be helpful.

    0
    2021-09-24T18:17:07+00:00

    Step-by-step explanation:

    Hi friend,

    Hi friend,By elimination method :

    Hi friend,By elimination method :8x+5y = 9———(1) ×2

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 18

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 9

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 95y = 9+16

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 95y = 9+165y = 25

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 95y = 9+165y = 25y = 25/5

    Hi friend,By elimination method :8x+5y = 9———(1) ×23x+2y = 4 —–(2). ×5we get,16x+10y = 1815x+10y= 20subtracting both the equations we get;x = -2Putting the value of x in (1)…8×-2 +5y = 9-16+5y = 95y = 9+165y = 25y = 25/5y = 5

    HOPE IT HELPS ❤️

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