Did you mean: Show that 12n cannot end with the digit 0 or 5 for any natural number n.

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If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. This is possible only if prime factorisation of 12n contains the prime number 5. Hence, there is no value of n e N for which 12n ends with digit zero or five.

Did you mean: Show that 12n cannot end with the digit 0 or 5 for any natural number n.

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If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. This is possible only if prime factorisation of 12n contains the prime number 5. Hence, there is no value of n e N for which 12n ends with digit zero or five.

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Answer:Did you mean: Show that 12n cannot end with the digit 0 or 5 for any natural number n.

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If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. This is possible only if prime factorisation of 12n contains the prime number 5. Hence, there is no value of n e N for which 12n ends with digit zero or five.

Did you mean: Show that 12n cannot end with the digit 0 or 5 for any natural number n.

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Featured snippet from the web

If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. This is possible only if prime factorisation of 12n contains the prime number 5. Hence, there is no value of n e N for which 12n ends with digit zero or five.

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Answer:there is a mistake in the question

12nend in 0(when n is a 10 multiple)

canbut 12n cannot end with zero

only numbers of the form 5×(odd number) will end with zero

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