Ram has 3 times as many ₹ 2 coins and he has ₹ 5 coins. If he has in all sum of ₹ 77 , how many coins of ₹ 2 does he have?

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Ram has 3 times as many ₹ 2 coins and he has ₹ 5 coins. If he has in all sum of ₹ 77 , how many coins of ₹ 2 does he have?

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Madeline 1 month 2021-10-29T22:22:19+00:00 2 Answers 0 views 0

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    0
    2021-10-29T22:23:35+00:00

    Answer:7

    Step-by-step explanation:

    Let us take number of 5 rupees coins as X and number of 2 rupees coins as Amount of 5 rupees coin will make = 5X  

    Amount of 2 rupees coin will make = 3Y

    Number of 2 rupees coin =   

    Number of 2 rupees coins are equal to 3X and number of 5 rupees is X

    Total amount = 2( 3X ) + 5X = 11X

    Now we can equate the amount which 11X = 77

    X = 7

    Now as we know the number of 2 rupees coin is 3X and number of 5 rupees coin is X, that means  

    Number of 2 rupees coins = 21 and number of 5 rupees coins = 7

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    0
    2021-10-29T22:24:00+00:00

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    \huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}

    \sf{\underline{\green{Given-}}}

    • Ram has 3 times as many ₹ 2 coins and he has ₹ 5 coins. He has in all sum of ₹ 77.

    \sf{\underline{\red{Find-}}}

    • How many coins of ₹ 2 does he have?

    \sf{\underline{\red{Answer-}}}

    • Ram have 7 coins of Rs 5 and 21 coins of Rs 2.

    \sf{\underline{\red{Explanation-}}}

    \sf{\underline{\green{ATQ-}}}

    • Number of Rs 2 coins is 3 times as number of Rs 5 coins.

    \sf \: Number \:  of \:  Rs \:  2  \: coins \:  = \:  3x

    ⠀⠀⠀⠀⠀⠀\begin{gathered}:\implies\sf\:2 × 3x = 6x\end{gathered}

    \sf \: Number \:  of \:  Rs \:  5  \: coins \:  = \:  x

    ⠀⠀⠀⠀⠀⠀\begin{gathered}:\implies\sf\:5 × x = 5x\end{gathered} \:

    As we know total amount Ram has = Rs 77

    ⠀⠀⠀⠀⠀⠀\begin{gathered}:\implies\sf\: 6x+5x=11x\end{gathered}

    ⠀⠀⠀⠀⠀⠀\begin{gathered}:\implies\sf\: 11x=77\end{gathered}

    ⠀⠀⠀⠀⠀⠀\begin{gathered}:\implies\sf\: x= \dfrac{7}{11} \end{gathered}

    ⠀⠀⠀⠀⠀⠀\begin{gathered}:\implies\sf\: x=7\end{gathered}

    ━━━━━━━━━━━━━━━━━

    \sf{\underline{\blue{Putting\:the\:values-}}}

    • \sf\:Number\:of\:Rs\:5\:coins=x=7
    • \sf\:Number\:of\:Rs\:2 \:coins\: =3x= 3 × 7 = 21

    ━━━━━━━━━━━━━━━━━

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