Q9 The areas of two similar triangles are respectively 16 cm² and 25 cm? Find the ratio of their corresponding sides. Ops: A. 03:4

Question

Q9 The areas of two similar triangles are respectively 16 cm² and 25 cm? Find the ratio of their corresponding sides.
Ops: A. 03:4
B. 02:3
C. 05:4
D. 04:5
YY7 and POR are 144 cm and 64 cm respectively. If the longest side of the niangle z , then the longest som​

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Piper 4 days 2021-10-10T00:32:51+00:00 1 Answer 0 views 0

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    2021-10-10T00:34:10+00:00

    Step-by-step explanation:

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    velavarajvel

    velavarajvel

    30.01.2019

    Math

    Primary School

    +5 pts

    Answered

    The areas of two similar triangles are 16 cm² and 25 cm² respectively. If the difference of their corresponding altitudes is 10 cm, find the lengths of altitudes.

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    THE BRAINLIEST ANSWER!

    Qvoeba26jd Ambitious

    Here is your solution :

    We know, Ar.(triangle1)/Ar.(triangle2) = Sq. of ratio of corresponding sides

    Let the ratio be x:y

    Then,

    x^2/Y^2 = 16/25

    (x/y)^2 = 16/25

    x/y = 4/5.

    Please mark as brainliest answer.

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    velavarajvel

    I need the answer with all the steps and altitude

    first thanks me

    later

    j will

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    9229635622

    9229635622 Ambitious

    Answer:

    Step-by-step explanation:

    Area(triangle1)/Area(triangle2) = Square of ratio of the corresponding sides

    Let the ratio be x:y

    Then,

    x2/Y2 = 16/25

    (x/y)2 = 16/25

    x/y = under root 16/25

    X/y = 4/5

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