## Q9 The areas of two similar triangles are respectively 16 cm² and 25 cm? Find the ratio of their corresponding sides. Ops: A. 03:4

Question

Q9 The areas of two similar triangles are respectively 16 cm² and 25 cm? Find the ratio of their corresponding sides.
Ops: A. 03:4
B. 02:3
C. 05:4
D. 04:5
YY7 and POR are 144 cm and 64 cm respectively. If the longest side of the niangle z , then the longest som​

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4 days 2021-10-10T00:32:51+00:00 1 Answer 0 views 0

1. Step-by-step explanation:

velavarajvel

velavarajvel

30.01.2019

Math

Primary School

+5 pts

The areas of two similar triangles are 16 cm² and 25 cm² respectively. If the difference of their corresponding altitudes is 10 cm, find the lengths of altitudes.

2

Qvoeba26jd Ambitious

We know, Ar.(triangle1)/Ar.(triangle2) = Sq. of ratio of corresponding sides

Let the ratio be x:y

Then,

x^2/Y^2 = 16/25

(x/y)^2 = 16/25

x/y = 4/5.

5.0

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5

velavarajvel

I need the answer with all the steps and altitude

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9229635622

9229635622 Ambitious

Step-by-step explanation:

Area(triangle1)/Area(triangle2) = Square of ratio of the corresponding sides

Let the ratio be x:y

Then,

x2/Y2 = 16/25

(x/y)2 = 16/25

x/y = under root 16/25

X/y = 4/5