Lata read 2/9 of a book on first day and 4/5 the remaining on second day. If 49 pages of the book are still of left unread, how many pages d

Question

Lata read 2/9 of a book on first day and 4/5 the remaining on second day. If 49 pages of the book are still of left unread, how many pages did the book contain?​

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Quinn 4 days 2021-10-10T11:03:36+00:00 2 Answers 0 views 0

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    0
    2021-10-10T11:04:46+00:00

    Step-by-step explanation:

    lata reads first day 2/9X

    then left 1X-2/9X=7/9X

    on second day she reads remaining 4/5X

    7/9x×4/5=28/45X

    then left of book=7/9X-28/45X=7/45X

    so, 7/45X=49

    X=49×45/7=7×45=315

    0
    2021-10-10T11:05:21+00:00

    Answer Step by step:

    Let the number of pages be x

    Number of pages read on the first day = 2x/9

    Number of pages read on the second day = 4x/5

    Number of the pages left to read = 49

    Total number of pages in the book = [49 + 2x/9 + 4x/5]=x

    => LCM- 45 => [2,205/45 + 10x/45 + 36x/45]=x => [36x/45 +2,205/45]=x

    =>  36x + 2,205 = 45x => 45x – 36x = 2,205 => 9x = 2,205 =>  x = 245

    Therefore, 245 pages are in the book.

    I HOPE THIS HELPS YOU OUT!!

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