(k-1) x²+kx + 1=3 find k. Please help me fast ​

Question

(k-1) x²+kx + 1=3 find k. Please help me fast ​

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Luna 2 months 2021-12-03T04:06:06+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-12-03T04:07:18+00:00

    Answer:

    Zero of the polynomial = -3

    p(-3) = (k-1) x (-3)²+k x -3 +1 =0

    ( k -1)9 -3k + 1 = 0

    9k – 9 – 3k + 1 =0

    6k – 8 =0

    6k = 8

    k = 8/6

    = 4/3

    Hope it helps..

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    Step-by-step explanation:

    0
    2021-12-03T04:07:32+00:00

    Step-by-step explanation:

    Zero of the polynomial = -3

    p(-3) = (k-1) x (-3)²+k x -3 +1 =0

    ( k -1)9 -3k + 1 = 0

    9k – 9 – 3k + 1 =0

    6k – 8 =0

    6k = 8

    k = 8/6

    = 4/3

    Hope it helps..

    Mark me as brainlist

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