In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system

Question

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system

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Lydia 3 weeks 2021-11-19T16:03:30+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-19T16:04:35+00:00

    Step-by-step explanation:

    Given : a cylindrical water heating system of lenght 28 m and diameter 5 cm

    To find out = radiating surface area

    Solution:

    As we know that total surface area is the radiating area here

    so height is 28m

    and radius is 5/2cm

    => tsa of cylinder => 2pir(r+h)

    => 2×22/7×5/2(5/2+2800)

    28m = 2800 cm

    => 110/7×2802.5

    => 110/7×28025/10

    => 11×4003

    => 44033 cm² approximately

    0
    2021-11-19T16:04:48+00:00

    Step-by-step explanation:

    Given:

    the height as h: 28m or 2800cm

    radius as r : 5cm/2 = 2,5cm

    csa of a cylinder = 2πrh

    => 2*22/7*2.5*2800

    =>44/7*7000

    =>44 * 1000

    =>44000cm²

    =>4.4m²

    thus the total radiating surface is 4.4 m²

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