## if x+y+z=20 and xy+yz+zx=100 then find the value of x*x+y*y+z*z​

Question

if x+y+z=20 and xy+yz+zx=100 then find the value of x*x+y*y+z*z​

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2 weeks 2021-11-19T15:19:24+00:00 1 Answer 0 views 0

300

Step-by-step explanation:

x + y + z = 20

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)400 = x² +y²+ z² + 100

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)400 = x² +y²+ z² + 100Therefore, x²+y²+ z² = 300

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)400 = x² +y²+ z² + 100Therefore, x²+y²+ z² = 300Hope it Helps you…

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)400 = x² +y²+ z² + 100Therefore, x²+y²+ z² = 300Hope it Helps you…Please mark me as brainliest