## If the sum of any two integers is 3 and the difference of the squares is 1 then the difference of them is

Question

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## Answers ( )

Answer:x+y=3=1x^2-y^2=(x+y)(x-y)3(x-y)=1

x-y=1/3

Answer:1/3

Step-by-step explanation:Let the two integers be ‘a’ and ‘b’

a+b=3

a²-b²=1

(a+b)(a-b) = 1

3(a-b) = 1

a-b = 1/3

∴ The difference of the numbers is 1/3

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