If the sum of any two integers is 3 and the difference of the squares is 1 then the difference of them is

Question

If the sum of any two integers is 3 and the difference of the squares is 1 then the difference of them is

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2 months 2021-08-24T15:01:13+00:00 2 Answers 0 views 0

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    0
    2021-08-24T15:02:42+00:00

    Answer:

    x+y=3

    x^{2} -y^{2}=1

    x^2-y^2=(x+y)(x-y)

    3(x-y)=1

    x-y=1/3

    0
    2021-08-24T15:02:52+00:00

    Answer:

    1/3

    Step-by-step explanation:

    Let the two integers be ‘a’ and ‘b’

    a+b=3

    a²-b²=1

    (a+b)(a-b) = 1

       3(a-b) = 1

    a-b = 1/3

    ∴ The difference of the numbers is 1/3

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