If roots of the quadratic equation px2-2√ 5 px+15 = 0 are real, then find the value of p. Question If roots of the quadratic equation px2-2√ 5 px+15 = 0 are real, then find the value of p. in progress 0 Math Mia 1 week 2022-01-15T09:01:20+00:00 2022-01-15T09:01:20+00:00 1 Answer 0 views 0

## Answers ( )

Answer:For real roots, discriminant must be greater than 0 or equal to 0.

Discriminant, for ax^2 + bx + c = 0, is given by b^2 – 4ac.

Here, b = -2

c = 15

a = p

= > discrimiant > 0

= > (-2)^2 – 4(15)p > 0

= > 20 – 60p > 0

= > 1/3 > p

Solution set for the values of p is { …0,1/9…1/4} or accurately, (-infinity,1/3 ).