If (3x – 4y ) = 4 and xy =1, find the value of 9x^2+16y^2​

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 If (3x – 4y ) = 4 and xy =1, find the value of 9x^2+16y^2​

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Charlie 1 month 2021-10-29T17:15:24+00:00 1 Answer 0 views 0

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    2021-10-29T17:16:52+00:00

    (3x-4y)²=16

    9x²+16y²-2•3X•4y=16

    9x²+16y²=16+24xy

    9x²+16y=40

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