if 3x+4y=11 and xy=12 then find the value of 27×3-64y3

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if 3x+4y=11 and xy=12 then find the value of 27×3-64y3

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Genesis 3 days 2021-10-12T13:35:22+00:00 1 Answer 0 views 0

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    2021-10-12T13:36:53+00:00

    Answer:

    1331 – 108x²y – 144xy²

    Step-by-step explanation:

    3x + 4y = 11

    Cubing on both sides,

    (3x + 4y)³ = 11³

    (a+b)³= a³ + 3a²b + 3ab² + b³

    Here, a = 3x and b = 4y

    (3x + 4y)³ = (3x)³ + (3 * 3x * 3x * 4y) + (3 * 3x * 4y * 4y) + (4y)³

          11³     = 27x³ + 108x²y + 144xy² + 64y³

          1331  = 27x³ + 108x²y + 144xy² + 64y³

    27x³ + 64y³ = 1331 – 108x²y – 144xy²

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