if (x+1) and (x-1) are the factors of p(x)=ax cube +x square -2x +b find the values of a and b The polynomials and when divided by leav

Question

if (x+1) and (x-1) are the factors of p(x)=ax cube +x square -2x +b find the values of a and b The polynomials and when divided by leave the remainders and respectively. If , find the value of ‘a’.

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Quinn 2 weeks 2021-11-19T18:17:23+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-19T18:18:44+00:00

    Step-by-step explanation:

    put x+1=0

    x= -1

    now,

    p(-1)=a(-1)³+(-1)²-2×(-1)+b

    = -a+1+2+b

    = -a+3+b

    according to question,

    p(-1)=0

    -a+3+b=0

    -a+b=-3

    put x-1=0

    x=1

    now,

    p(1)=a(1)³+(1)²-2×1+b

    = a+1-2+b

    = a-1+b

    according to question,

    p(1)=0

    -a-1+b=0

    a+b=1

    value of a= remainder of 1 – remainder of 2

    = -a+b= -3

    a+b= 1

    _________

    -2a. = -4

    a= -4/-2

    a=2

    put in equation 2

    a+b=1

    2+b=1

    2-1=b

    1=b

    0
    2021-11-19T18:19:06+00:00

    Answer:

    a=2 b=0 hopefully this helps

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