For what value of min 2x³+mx²+11x+m+3 is exactly divisible by 2x-1 Question For what value of min 2x³+mx²+11x+m+3 is exactly divisible by 2x-1 in progress 0 Math Eva 7 days 2021-10-10T22:38:22+00:00 2021-10-10T22:38:22+00:00 2 Answers 0 views 0

## Answers ( )

Answer: -43Step-by-step explanation:if given polynomial is divisible by 2x-1, then2x-1 is a factor of 2x^3+mx^2+11x+3therefore, putting x=1/2 in the given polynomial gives remainder zerohence, 2(1/2)^3 + m(1/2)^2 + 11(1/2) + 3 =0solving above eq. we get2*(1/8) + m*(1/4) + (11/2) + 3 = 01/4 + m/4 + 22/4 + 12/4 = 01+m+22+12 = 0m = -43Answer:THIS IS YOUR ANSWER PLS FOLLOW ME AND PLS MARK AS BRAINLIEST