For what value of min 2x³+mx²+11x+m+3 is exactly divisible by 2x-1

Question

For what value of min 2x³+mx²+11x+m+3 is exactly divisible by 2x-1

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Eva 7 days 2021-10-10T22:38:22+00:00 2 Answers 0 views 0

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    0
    2021-10-10T22:39:40+00:00

    Answer:  -43

    Step-by-step explanation:

    if given polynomial is divisible by 2x-1, then

    2x-1 is a factor of 2x^3+mx^2+11x+3

    therefore, putting x=1/2 in the given polynomial gives remainder zero

    hence, 2(1/2)^3 + m(1/2)^2 + 11(1/2) + 3 =0

    solving above eq. we get

    2*(1/8) + m*(1/4) + (11/2) + 3 = 0

    1/4 + m/4 + 22/4 + 12/4 = 0

    1+m+22+12 = 0

    m = -43

    0
    2021-10-10T22:40:19+00:00

    Answer:

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