.Find the value of k for which the quadratic equation has equal roots 3x^2-5x+k=0

Question

.Find the value of k for which the quadratic equation has equal roots 3x^2-5x+k=0

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Skylar 2 months 2021-11-23T05:00:46+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-23T05:02:10+00:00

    Answer:

     \large{k =  \frac{25}{12} }

    Step-by-step explanation:

     \text{for \: }a {x}^{2}  + bx + c = 0  \text{\: to \: have \: equal \: roots} \\  \\  {b}^{2}  = 4ac \\  \\  \text{given} \quad \: 3 {x}^{2}   - 5x + k = 0 \\  \\  =  > a = 3 \quad \: b =  - 5 \quad \: c = k \\  \\  =  >  {( - 5)}^{2}  = 4(3)(k) \\  \\  =  > 12k = 25 \\  \\  =  > k =  \frac{25}{12}

    HOPE IT HELPS

    0
    2021-11-23T05:02:30+00:00

    Answer:

    \large{k = \frac{25}{12} }k=

    12

    25

    Step-by-step explanation:

    \begin{gathered}\text{for \: }a {x}^{2} + bx + c = 0 \text{\: to \: have \: equal \: roots} \\ \\ {b}^{2} = 4ac \\ \\ \text{given} \quad \: 3 {x}^{2} – 5x + k = 0 \\ \\ = > a = 3 \quad \: b = – 5 \quad \: c = k \\ \\ = > {( – 5)}^{2} = 4(3)(k) \\ \\ = > 12k = 25 \\ \\ = > k = \frac{25}{12}\end{gathered}

    for ax

    2

    +bx+c=0to have equal roots

    b

    2

    =4ac

    given3x

    2

    −5x+k=0

    =>a=3b=−5c=k

    =>(−5)

    2

    =4(3)(k)

    =>12k=25

    =>k=

    12

    25

    hope it helps you mark brainliest

    HOPE IT HELPS

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