find the value of x cube minus 3 x square Y + 2 XY Square + 8 xy + 9 When X is equal to -3 and Y is equal to 1

Question

find the value of x cube minus 3 x square Y + 2 XY Square + 8 xy + 9 When X is equal to -3 and Y is equal to 1

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Adalyn 4 days 2021-10-10T01:10:43+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-10-10T01:11:55+00:00

    Step-by-step explanation:

    Here,

    QUESTION :

    x³ 3x²y + 2xy² + 8xy + 9

    GIVEN VALUE :

    X = 3

    Y = 1

    SOLUTION :

    X³ 3x²y + 2xy² + 8xy + 9

    substituting the value of x and y ,

    = ( 3)³ 3 × ( 3)² × 1 + 2× (3) × 1² + 8×(3)×1 + 9

    = 27 27 + ( 6) + ( 24) + 9

    = 27 27 6 24 + 9

    = 84 + 9

    = 75 answer

    Thanks you

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