find the value of x cube minus 3 x square Y + 2 X Square + 8 xy + 9 then X is equal to -3 and Y is equal to 1

Question

find the value of x cube minus 3 x square Y + 2 X Square + 8 xy + 9 then X is equal to -3 and Y is equal to 1

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Kennedy 4 days 2021-10-10T03:23:27+00:00 2 Answers 0 views 0

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    0
    2021-10-10T03:24:39+00:00

    Answer:

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    {x}^{3}  -  {3}x^{2} y + 2 {x}^{2}   + 8xy + 9 \: \\  then \\ x =  - 3 \\ and \\  \\ y = 1

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    0
    2021-10-10T03:24:51+00:00

    Answer:

    3

    Step-by-step explanation:

    x^3=(-3)^3=-27

    3x^2*y=3(-3)^2*1=27

    2x^2=2*(-3)^2=18

    8xy=8*(-3)*1=-24

    9=9

    x cube minus 3 x square Y + 2 X Square + 8 xy + 9=-27+27+18-24+9

                                                                                        =18+9-24

                                                                                        =27-24

                                                                                        =3

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