Find the smallest number which leaves a remainder of 5 when divided by 24,32 and 42. Find the smallest​

Question

Find the smallest number which leaves a remainder of 5 when divided by 24,32 and 42.
Find the smallest​

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Adalyn 4 days 2021-10-11T05:48:21+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-11T05:50:01+00:00

    Step-by-step explanation:

    When smaller number we should do LCM but if larger number we should do HCF.

    I hope it helps you

    0
    2021-10-11T05:50:14+00:00

    Answer:

    677

    Step-by-step explanation:

    Let the number be ‘N’.

    Now N, when divided by 24, 32 & 42 leaves remainder 5.

    In other words, (N-5) will be complely divisible by 24, 32 and 42 and the least as well.

    So, (N-5) has to be the LCM of 24, 32 & 42.

    LCM (24, 32, 42) = 672 = (N-5)

    So, N = 677 (Answer)

    Note: In general, if we have multiple Divisors giving the same Remainder, then the number is given as:

    [N = LCM of Divisors + Remainder]

    Hope this helps u.

    Mark this as brainliest answer

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