. Find the remainder when p(x) = 9x^3 – 3x^2 + x – 5 is divided by x – 2/3.​

Question

. Find the remainder when p(x) = 9x^3 – 3x^2 + x – 5 is divided by x – 2/3.​

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Julia 18 hours 2021-10-12T16:45:47+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-12T16:47:22+00:00

    Answer:

    p(x)=3x²+x-5

    q(x)=x-2/3

    remainder(x)=3x+5/3

    0
    2021-10-12T16:47:42+00:00

    Step-by-step explanation:

    X-2/3=0

    X=2/3

    9X^3-3X^2+X-5

    9(2/3)^3-3×(2/3)^2+2/3-5

    9×8/27-3×4/9+2/3-5

    8/3-4/3+2/3-5

    6/3-5

    2-5= -3

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14:4+1-6*5-7*14:3+5 = ? ( )