find the rate of compound interest for ₹10000amount to 11000 in 2 years Question find the rate of compound interest for ₹10000amount to 11000 in 2 years in progress 0 Math Luna 1 month 2021-10-28T00:13:27+00:00 2021-10-28T00:13:27+00:00 1 Answer 0 views 0

## Answers ( )

Answer:Rate=4.8%p.a.

Step-by-step explanation:P= 10000RS.

A=11000RS.

T=2yrs.

A=P(1+r/100)^2

=>11000=10000(1+r/100)^2

=>

11000=(1+r/100)^210000

=>11/10=(1+r/100)^2

=>sq.root of 11/10=1+r/100

=>1.048-1=r/100

=>0.048=r/100

=>r=0.048×100

=>r=4.8%p.a.

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