## Find the factors of : 2×3 – 3×2 – 11x + 6 Select one: a. (x+2) (x+3)(2x-1) b. (x+2) (x-3)(2x-1) c. (x-2) (x+3)(2x+1) d. (x-2) (x-3)(2x+1)

Question

Find the factors of : 2×3 – 3×2 – 11x + 6 Select one: a. (x+2) (x+3)(2x-1) b. (x+2) (x-3)(2x-1) c. (x-2) (x+3)(2x+1) d. (x-2) (x-3)(2x+1)

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1 week 2021-10-04T18:32:30+00:00 1 Answer 0 views 0

Step-by-step explanation:

If plugging x = a into a polynomial yields -zero, then the

polynomial has (x – a) as a factor.

We’ll use this fact to try to find factors of x3 + 3×2 – 4 . We look for

factors (x-a) by plugging in various possible a’s , choosing those that

are factors of -4 . Try plugging x 1-12 2 4, -4 into

x3+3×2-4. Findthat x-I gives 13+3.12-4 -0. So x-1 isa

factor of x3 + 3×2 – 4 . To factor it out, perform long division:

x2 + 4x + 4 Thus

x-~ lx3 + sx2+ Ox – ~3 + 3×2 – 4 = (x-I)(x~ + 4x + 4).

x3 – .2 But x2 + 4x + 4 can be

4×2 + Ox – 4 factored further as in the

4×2 – 4x examples above;