Find the factors of : 2×3 – 3×2 – 11x + 6 Select one: a. (x+2) (x+3)(2x-1) b. (x+2) (x-3)(2x-1) c. (x-2) (x+3)(2x+1) d. (x-2) (x-3)(2x+1)

Question

Find the factors of : 2×3 – 3×2 – 11x + 6 Select one: a. (x+2) (x+3)(2x-1) b. (x+2) (x-3)(2x-1) c. (x-2) (x+3)(2x+1) d. (x-2) (x-3)(2x+1)

in progress 0
Gabriella 1 week 2021-10-04T18:32:30+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-10-04T18:33:42+00:00

    Answer:

    Hope this will help you

    Please mark me as brainleast

    Step-by-step explanation:

    If plugging x = a into a polynomial yields -zero, then the

    polynomial has (x – a) as a factor.

    We’ll use this fact to try to find factors of x3 + 3×2 – 4 . We look for

    factors (x-a) by plugging in various possible a’s , choosing those that

    are factors of -4 . Try plugging x 1-12 2 4, -4 into

    x3+3×2-4. Findthat x-I gives 13+3.12-4 -0. So x-1 isa

    factor of x3 + 3×2 – 4 . To factor it out, perform long division:

    x2 + 4x + 4 Thus

    x-~ lx3 + sx2+ Ox – ~3 + 3×2 – 4 = (x-I)(x~ + 4x + 4).

    x3 – .2 But x2 + 4x + 4 can be

    4×2 + Ox – 4 factored further as in the

    4×2 – 4x examples above;

Leave an answer

Browse

14:4+1-6*5-7*14:3+5 = ? ( )