Find the area between the curves y=2/x and y=−x+3.

Question

Find the area between the curves y=2/x and y=−x+3.

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Hailey 2 months 2021-12-03T07:40:21+00:00 2 Answers 0 views 0

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    0
    2021-12-03T07:42:02+00:00

    Answer:

    A=∫ba|=∫π0|sinx−cosx|dx=∫π/40(cosx−sinx)dx+∫ππ/4(sin=[sinx+cosx]|π/40+[−cos=(√2−1)+(1+ The area of the region is 2√2 units2. If R is the region between the graphs of the functions f(x)=sinx and g(x)=cosx over the interval [π/2,2π], find the area of region R.

    Step-by-step explanation:

    0
    2021-12-03T07:42:07+00:00

    Step-by-step explanation:

    The area enclosed between y

    2

    =x and y=x

    October 15, 2019

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    Hashmat Shaikh

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    VIDEO EXPLANATION

    ANSWER

    Intersection point of two curves are O(0,0) and A(1,1)

    ∴ Required area =∫

    0

    4

    (y

    2

    −y

    1

    )dx

    0

    1

    (

    x

    −x)dx

    =[

    3/2

    x

    3/2

    2

    x

    2

    ]

    0

    1

    =

    3

    2

    [1−0]−

    2

    1

    (1−0)

    =

    3

    2

    2

    1

    =

    6

    1

    unit

    solution

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