find 2 consecutive positive odd numbers the sum of whose square is 74​

Question

find 2 consecutive positive odd numbers the sum of whose square is 74​

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Iris 3 days 2021-10-11T07:06:52+00:00 2 Answers 0 views 0

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    0
    2021-10-11T07:08:09+00:00

    Answer:

    THE WAY OF EASIET METHOD YOUR ANSWER IS HERE MATE

    let no. be x & x+2.

    then, x^2 + (x+2)^2 =74

    x^2 +x^2+4+2x=74

    then,

    2x^2 +2x+4-74=0

    x^2+ 2x+2-37=0

    x^2+2x-35=0

    x^2+7x-5x-35=0

    x(x+7)-5(x+7)=0

    (x-5)(x+7)=0

    x=5 & x=-7

    Step-by-step explanation:

    HOPE IT HELP U.

    MARK BRAINLIEST TOO PLEASE

    0
    2021-10-11T07:08:40+00:00

    Answer:

    \bold{The\ 2\ consecutive\ numbers\ are\ 5\ and\ 7.}

    Step-by-step explanation:

    So let the 1st odd number be x, so the 2nd odd number will be x + 2.

    Why x + 2? because if the odd number is 5 so the next odd number will be 7 or 5 + 2.

    So putting the variables into equation…

    By factorisation

    x² + (x + 2)² = 74

    x² + x² + 4x + 4 = 74

    2x² + 4x + 4 = 74

    2x² + 4x = 70

    2x² + 4x -70 = 0

    x² + 2x – 35 = 0

    x² +7x -5x -35 = 0

    x(x + 7) -5(x + 7) = 0

    (x – 5) (x + 7) = 0

    x = 5 and 7

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14:4+1-6*5-7*14:3+5 = ? ( )