Factorise (x2−4x) (x2-4x-1-20) please answer

Question

Factorise (x2−4x) (x2-4x-1-20) please answer

in progress 0
Camila 3 months 2021-10-15T16:59:04+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-15T17:00:34+00:00

    Answer:

    Step-by-step explanation:

    (x^{2} - 4x) (x^{2} - 4x - 1 - 20)

    (x^{2} - 4x) (x^{2} - 4x - 21)

    (x^{2} - 4x) (x^{2} + 3x - 7x - 21)\\\\= (x^{2} - 4x) [x ( x + 3 ) - 7( x + 3 )]\\\\= (x^{2} - 4x)(x - 7)( x + 3 )\\\\= [x^{2} - (2\sqrt{x})^{2} ] (x - 7)( x + 3 )

    using a^{2} - b^{2} = (a + b)(a – b)

    =(x + 2\sqrt{x}) (x - 2\sqrt{x}) (x - 7) (x + 3)

    0
    2021-10-15T17:00:36+00:00

    Answer:

    x (x-4) (x-3) (x+7)

    Step-by-step explanation:

    (X²-4x) (x²-4x-1-20)

    (X²-4x) (x²-4x-21)

    x(x-4) (x²-3x+4x-21)

    X(x-4) (x(x-3)+7(x-3))

    x (x-4) (x-3) (x+7)

Leave an answer

Browse

14:4+1-6*5-7*14:3+5 = ? ( )