Divide 180 into two part which are in the ratio 3:2​

Question

Divide 180 into two part which are in the ratio 3:2​

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Aubrey 3 days 2021-10-12T16:19:20+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-12T16:20:44+00:00

    Answer:

    let the ratio be 3x&2x

    3x+2x=180 since we have to divide 180 in the ratio of 3:2

    5x=180x

    x=180/5

    x=36

    0
    2021-10-12T16:21:11+00:00

     \sf \color{lime}{Question : }

     \sf{divide \:  180  \: into \:  two \:  parts  \: in  \: ratio  \: 2: 3}

     \sf \red{Analysis}

    As given, we need to find two numbers that satisfy the ratio 2:3 and their sum must me 180. So we can take 2x + 3x = 180. So we have got the equation, Let’s get started

     \sf \color{maroon}{Solution}

     \sf{  : : : \implies2x + 3x = 180}

    \sf{  : : : \implies5x = 180}

    \sf{  : : : \implies x = \frac{180}{5} } \\

    \sf \blue{  : : : \implies x = 36}

     \sf{now, \: let \: us \: find \: the \: value \: of \: 2x \: and \: 3x}

    \sf \pink{  : : : \implies 2x = 36 \times 2 = 72} \\ \sf \pink{  : : : \implies3x = 36 \times 3 = 108}

     \sf \green{Verification}

     \sf \purple{ \underbrace{ \overbrace{72 + 108 = 180}}}[tex] \sf \huge\color{orange}{ \checkmark}[/tex]

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