Detemine the nature of roots of the quadratic equation x2-6x+9=0

Question

Detemine the nature of roots of the quadratic equation x2-6x+9=0

in progress 0
Ella 2 weeks 2021-11-15T08:03:38+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-15T08:05:24+00:00

    Given ,

    • The polynomial is x² – 6x + 9

    Here ,

    a = 1

    b = -6

    c = 9

    We know that , the discriminant of polynomial is given by

     \boxed{ \sf{D =  {(b)}^{2} - 4ac }}

    Thus ,

    D = (-6)² – 4 × 1 × 9

    D = 36 – 36

    D = 0

    Therefore ,

    • The nature of roots are real and equal

    0
    2021-11-15T08:05:37+00:00

    Step-by-step explanation:

    D=b^2-4ac

    where,a=1,b=-6,c=9

    D=(-6)^2-4×9

    D=36-36

    D=0

    Therefore,the roots are real and equal

    This is the answer.

Leave an answer

Browse

14:4+1-6*5-7*14:3+5 = ? ( )