Cos (theeta-alpha) =a sin (theeta-beta)= b then, cos^2(alpha-beta) + 2ab sin(alpha-beta)= ​

Question

Cos (theeta-alpha) =a
sin (theeta-beta)= b
then,
cos^2(alpha-beta)
+ 2ab sin(alpha-beta)=

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Melanie 3 months 2021-10-15T17:58:00+00:00 1 Answer 0 views 0

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    2021-10-15T17:59:28+00:00

    Answer:

    If cos(theta-alpha) = a and cos( theta-beta) = b then the value of sin^2(alpha- beta) + 2ab cos(alpha-beta)

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