by which least number should 243 be multiplied so that it is a perfect square?find the perfect square number. also,find the square root​

Question

by which least number should 243 be multiplied so that it is a perfect square?find the perfect square number. also,find the square root​

in progress 0
Skylar 3 months 2021-11-06T16:49:25+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-06T16:51:00+00:00

    Answer:

    HEY MATE,HERE’S YOUR ANSWER ..

    Step-by-step explanation:

    There are two ways of solving this problem. The most obvious approach is to multiply it by the lowest natural numbers in increasing order, so first 1, then 2, then 3 and so on, and stop as soon as the product is a perfect cube. The second approach is to find the prime factorization of 243 and use it to find the lowest factor that 243 can be multiplied by such that all prime divisors of the product (and 243) are raised to a power divisible by 3 in the product. Since 243 = 3^5, the answer is 3 because 3^5 * 3 = 3^6 which is a perfect cube since 6 is divisible by 3.

    PLEASE MARK ME AS THE BRAINLIEST..

    0
    2021-11-06T16:51:16+00:00

    Answer:

    Step-by-step explanation:

     (i) We have 243 = 3 × 3 × 3 × 3 × 3

                     

                     The prime factor 3 is not a group of three.                  ∴ 243 is not a perfect cube.                  Now, [243] × 3 = [3 × 3 × 3 × 3 × 3] × 3                  or 729 =3 × 3 × 3 × 3 × 3 × 3                  Now, 729 becomes a perfect cube.                  Thus, the smallest required number to multiply 243 to make it a perfect cube is 3.

Leave an answer

Browse

14:4+1-6*5-7*14:3+5 = ? ( )