An ore contains 20%zinc. How many kg of ore will be required to get 90 kg of zinc​

Question

An ore contains 20%zinc. How many kg of ore will be required to get 90 kg of zinc​

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Aubrey 2 months 2021-11-23T01:45:44+00:00 2 Answers 0 views 0

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    0
    2021-11-23T01:47:02+00:00

    Answer:

    20/100×a=45

    a=45×100

    a=45×5

    there are a=225 kg ore required

    I hope you like it

    0
    2021-11-23T01:47:18+00:00

    Answer:

    Let the quantity of ore be x.

    Zinc = 20% = 20/100

    A/Q,

    20/100 × x = 90

    x / 5 = 90

    x = 90 × 5

    x = 450kg ans.

    Step-by-step explanation:

    Hope it helps.

    20thnks: Inbox.

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