An ore contains 20%zinc. How many kg of ore will be required to get 90 kg of zinc Question An ore contains 20%zinc. How many kg of ore will be required to get 90 kg of zinc in progress 0 Math Aubrey 2 months 2021-11-23T01:45:44+00:00 2021-11-23T01:45:44+00:00 2 Answers 0 views 0

## Answers ( )

Answer:20/100×a=45

a=45×100

a=45×5

there are a=225 kg ore required

IhopeyoulikeitAnswer:## Let the quantity of ore be x.

## Zinc = 20% = 20/100

## A/Q,

## 20/100 × x = 90

## x / 5 = 90

## x = 90 × 5

## x = 450kg ans.

Step-by-step explanation:Hope it helps.20thnks:Inbox.