an elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level how long will it take to

Question

an elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level how long will it take to reach -350m deep under the ground​. please help fast Give clear explanation also​

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Isabelle 1 month 2021-10-19T00:19:55+00:00 1 Answer 0 views 0

Answers ( )

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    2021-10-19T00:21:44+00:00

    ANSWER ;

    3600 seconds

    Step-by-step explanation:

    total distance the elevator has to cover = 360 metre

    velocity = 6m/min   =  6/60 m/s   =   0.1 m/s

    Use the formula t= S/v  

              t = 360/0.1    

              t = 3600 seconds  = 60 minutes   = 1 hour

    Hope you are satisfied by my answer

    Mark me as brainliest…….

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