a two digit number is four times the sum of its digit and twice the product . find the no.​

Question

a two digit number is four times the sum of its digit and twice the product . find the no.​

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Alaia 4 months 2021-09-24T15:35:28+00:00 1 Answer 0 views 0

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    2021-09-24T15:37:08+00:00

    Answer:

    Step-by-step explanation:

    let the two digit number be 10x + y

    according to the given question ,

    Ist case

    10x +y = 4(x+y)

    10x +y = 4x +4y

    10x – 4x = 4y – y

    6x = 3y

    divide by 3 throughout

    2x = y

    2x – y =0 ….[1]

    2nd case

    10x +y = 2(x+y)

    10x +y = 2x+2y

    10x -2x = 2y – y

    8x = y

    8x – y = 0….[2]

    solve 1,2

    2x – y = 0 [1]

    8x – y = 0 [2]

    subtract ;

    we get – -6x = 0

    x = 0

    put x=0 in [1]

    2(0) – y = 0

    0-y = 0

    y = 0

    therefore the solution for this solution is x,y (0,0)

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