A sum of Rs 2700 is to be given in the form of 63 prices .If the price of either Rs 100 or R 25, find the numbers of prices each types answe

Question

A sum of Rs 2700 is to be given in the form of 63 prices .If the price of either Rs 100 or R 25, find the numbers of prices each types answer step by step

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Liliana 2 months 2021-11-23T02:37:28+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-23T02:38:47+00:00

    Answer:

    100 prizes = 15

    25 prizes = 48

    Step-by-step explanation:

    Given :

    • Total sum of the prices to be given = 63
    • Total amount of all prices = 2700
    • They are either of denominations rs. 100 or rs. 25

    To find :

    • Number of prices of each type

    Let number of rs. 100 prices = X

    Let number of rs. 25 prices = Y

    X+Y = 63 – – – (1)

    Now for other condition:

    100X+25Y = 2700

    4X + Y = 108 – – – – (2)

    (2)-(1) :

    4X + Y – (X + Y) = 108-63

    4X + Y – X – Y = 45

    3X = 45

    X = 15

    Substituting the value Of X in equation 1 = 4(15)+y = 108

    60+y=108

    y = 48

    15 rupees 100 prizes and 48 rupees 25 prizes are to be given

    0
    2021-11-23T02:39:06+00:00

    \huge\sf\pink{Answer}

    ☞ 15-100 Rupee prizes and 48-25 Rupee prizes is Yourur Answer

    \rule{110}1

    \huge\sf\blue{Given}

    ✭ Total amount to be given = 2700

    ✭ Total Number of prices = 63

    ✭ The price is either of Rs 100 or Rs 25

    \rule{110}1

    \huge\sf\gray{To \:Find}

    ◈ Number of prices of each type

    \rule{110}1

    \huge\sf\purple{Steps}

    Answer:

    100 prizes = 15

    25 prizes = 48

    Step-by-step explanation:

    Assume that,

    ◕ Number of 100 Ruppee prices as x

    ◕ Number of 25 Rupee prices be y

    \bullet\:\underline{\textsf{As Per the Question}}

    \sf x+y = 63\qquad -eq(1)

    And also,

    \sf 100x+25y = 2700

    \sf 4x + y = 108 \qquad-eq(1)

    Subtracting eq(1) from eq(2)

    \sf 4x + y - (x + y)  = 108-63

    \sf 4x + y - x - y = 45

    \sf 3x = 45

    \sf\red{x = 15}

    Substituting the value of x in eq(1)

    \sf 4(15)+y = 108

    \sf 60+y=108

    \sf\orange{y = 48}

    \rule{170}3

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