A sum of Rs 1000 is invested at 8% per annum simple interest. Calculate the Interest at the end of 1,2,3… years. Is the sequence of i

Question

A sum of Rs 1000 is invested at 8% per annum simple interest. Calculate the
Interest at the end of 1,2,3… years. Is the sequence of interest an AP? Find the
interest at the end of 30 years.​

in progress 0
Madeline 1 week 2021-10-04T21:23:47+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-04T21:25:14+00:00

    GIVEN:-

    ⟹ P = ₹ 1000

    ⟹ R = 8%

    ⟹ T = 1, 2 and 3

    TO FIND:-

    • The interest at the end of the year.
    • The interest at the end of 30 years.

    SOLUTION:-

    S.I = P×R×T/100

    So,

    The interest at the end of the 1st year:

    ⟹ ₹ 1000×8×1/100

    ₹80

    The interest at the end of the 2nd year:

    ⟹ ₹ 1000×8×2/100

    ₹160

    The interest at the end of the 3rd year:

    ⟹ ₹ 1000×8×3/100

    ₹240

    Therefore, the interest(in ₹) at the end of 1st, 2nd and 3rd year years are 80,160,240.

    It is an AP is the difference between the consecutive terms in the list is 80, that is d = 80 also a = 80.

    So, to find the interest at the end of 30 years we shall find a30.

    a30 = a+(30-1)d

    a30 = 80+29×80

    a30 = 2400

    So, the interest at the end of 30 years will be ₹2400.

    0
    2021-10-04T21:25:22+00:00

    Given,

    principal=1000

    rate of interest=8%

    number of years=1 year

    SI=Pnr/100=1000x1x8/100=rs.80

    when n=2 years,SI=1000x2x8/100=rs.160

    when n=3years,SI=1000x3x8/100=rs.240

    the sequence is

    80,160,240,……….

    this is in AP as a,first term=80,d,common difference=80

    interest at the end of 30 years,t30=a+(n-1)d

    =80+(30-1)80

    =80+29(80)

    =80+2320

    =2400

    please,if you like it rate it as the best and thank this comment

Leave an answer

Browse

14:4+1-6*5-7*14:3+5 = ? ( )