A man had some milk. When he sold 3/4 parts of the quantity of milk, 15 / was left. How much milk did he have in the beginning? could you pl

Question

A man had some milk. When he sold 3/4 parts of the quantity of milk, 15 / was left. How much milk did he have in the beginning? could you please explain step by step. pleaseeeeeeeeeeeeeeeee

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Evelyn 2 months 2021-12-03T03:44:51+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-12-03T03:46:28+00:00

    Answer:

    20 litre

    Step-by-step explanation:

    20 litre is the right answer of this question

    0
    2021-12-03T03:46:44+00:00

    Answer:

    A container contains 40 litres of milk. From this container, 4 litres of milk were taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

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    Let me tell you a cool trick/formula to solve such problems.

    Let there be ‘N’ litres of milk initially.

    ‘P’ litres are taken out & replaced by water……….( for the 1st time )

    ‘P’ litres are taken out & replaced by water……….( for the 2nd time )

    ‘P’ litres are taken out & replaced by water……….( for the 3rd time )

    ‘P’ litres are taken out & replaced by water……….( for the 4th time )

    ————————————————————————-

    ‘P’ litres are taken out & replaced by water……….( for the ‘n’th time )

    Then,

    Milk = ( 1 – P/N )^n

    —— —————–

    Water 1 – ( 1 – P/N )^n

    Milk = Milk = ( 1 – P/N )^n

    ——— – ————–

    Solution Milk + Water

    Water = Water = 1 – ( 1 – P/N )^n

    ——— – ————–

    Solution Milk + Water

    For your Question:

    N=40

    P=4

    n=3

    Milk (M) = ( 1 – 4/40)^3 = 0.9^3

    ————–

    Solution(40)

    => M = 40* (0.9)^3 = 29.16

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