## A man had some milk. When he sold 3/4 parts of the quantity of milk, 15 / was left. How much milk did he have in the beginning? could you pl

Question

A man had some milk. When he sold 3/4 parts of the quantity of milk, 15 / was left. How much milk did he have in the beginning? could you please explain step by step. pleaseeeeeeeeeeeeeeeee

in progress 0
2 months 2021-12-03T03:44:51+00:00 2 Answers 0 views 0

20 litre

Step-by-step explanation:

20 litre is the right answer of this question

A container contains 40 litres of milk. From this container, 4 litres of milk were taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

OnePlus 8 5G series on Amazon Prime Day.

Let me tell you a cool trick/formula to solve such problems.

Let there be ‘N’ litres of milk initially.

‘P’ litres are taken out & replaced by water……….( for the 1st time )

‘P’ litres are taken out & replaced by water……….( for the 2nd time )

‘P’ litres are taken out & replaced by water……….( for the 3rd time )

‘P’ litres are taken out & replaced by water……….( for the 4th time )

————————————————————————-

‘P’ litres are taken out & replaced by water……….( for the ‘n’th time )

Then,

Milk = ( 1 – P/N )^n

—— —————–

Water 1 – ( 1 – P/N )^n

Milk = Milk = ( 1 – P/N )^n

——— – ————–

Solution Milk + Water

Water = Water = 1 – ( 1 – P/N )^n

——— – ————–

Solution Milk + Water

N=40

P=4

n=3

Milk (M) = ( 1 – 4/40)^3 = 0.9^3

————–

Solution(40)

=> M = 40* (0.9)^3 = 29.16