A man had some milk. When he sold 3/4 parts of the quantity of milk, 15 / was left. How much milk did he have in the beginning? could you pl

Question

A man had some milk. When he sold 3/4 parts of the quantity of milk, 15 / was left. How much milk did he have in the beginning? could you please explain step by step

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Allison 2 months 2021-12-03T04:01:53+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-12-03T04:03:03+00:00

    • Given –

    • 3/4 milk has been sold
    • after selling 3/4 milk, 15 litres is left

    • To Find –

    • How much milk he had in beginning (Total)

    Solution

    First of all, let’s convert left out of milk in it’s original form i.e (Simplifying)

    ⟹left \: milk = 1 -  \frac{3}{4}

    (Here, 3/4 is compared to 1)

    ⟹left \: milk =  \frac{4}{4}  -  \frac{3}{4}.. (Cross Multiplying)

    ⟹left \: milk =  \frac{1}{4}.. (Common Denominator)

    Now! let’s suppose total milk in beginning be x

    So, It will be,

    ⟹ \frac{1}{4}  x  = 15

    ⟹x = 15 \times 4.. (Transferring Values)

    \huge\boxed{x = 60}

    ⛬ Total Milk in beginning was 60 litres

    0
    2021-12-03T04:03:52+00:00

    Answer:

    60 litres

    Step-by-step explanation:

    Given:

    • \frac{3}{4} of the total milk was sold
    • after \frac{3}{4} of the total milk is sold 15 litres arre left out

    To find:

    • How much milk he had in the beginning

    Left out milk = 1-\frac{3}{4}

    Left out milk = \frac{4}{4} - \frac{3}{4}

    Left out milk = \frac{1}{4}

    Let the total milk be equal to X

    so,

    \frac{1}{4} X = 15

    X=15×4

    X=60 litres

    He had 60 litres of milk at the beginning

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