A chord of a circle of radius 14 cm subtends an angle of 90° at the ante find the area of the corresponding major segment of the c

Question

A chord of a circle of radius 14 cm subtends an angle of
90° at the ante find the area of the corresponding
major segment of the circle​

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Adalynn 3 days 2021-11-25T07:16:23+00:00 1 Answer 0 views 0

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    2021-11-25T07:17:53+00:00

    Answer:

    Step-by-step explanation:

    Given radius (r) = 14cm = OA = OB

    θ = angle at centre = 60°

    In ΔAOB, ∠A = ∠B [angles opposite to equal sides OA and OB] = x

    By angle sum property ∠A + ∠B + ∠O = 180°

    x + x + 60° = 180° ⇒ 2x = 120° ⇒ x = 60°

    All angles are 60°, OAB is equilateral OA = OB = AB

    Area of minor segment = area of sector – area of ΔOAB

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